Martin sold his computer and software for $900.00, receiving three times as much for the computer then the software. What was the selling price of the computer and software?

s + 3s = 900

4s = 900

s = 225

The price of the software was $225.

To solve this problem, let's represent the selling price of the computer as "C" and the selling price of the software as "S".

Given the information in the question, we know that Martin sold his computer and software for a total of $900.00. We also know that the selling price of the computer was three times the selling price of the software.

Therefore, we can write two equations based on this information:

1. The total selling price of the computer and software is $900.00:
C + S = 900

2. The selling price of the computer is three times the selling price of the software:
C = 3S

Now we can solve this system of equations using substitution or elimination.

Let's use substitution:
Substituting C in equation 1 with its value from equation 2, we get:
3S + S = 900
4S = 900
S = 225

Now, substitute the value of S back into equation 2 to find the value of C:
C = 3(225)
C = 675

Therefore, the selling price of the computer is $675.00 and the selling price of the software is $225.00.