posted by Max on .
What is the maximum height achieved if a 0.800 kg mass is thrown straight upward with an initial speed of 40.0 m·s–1? Ignore the effect of air resistance.
Thats what it looks like.. but im taking chem. in college and have never had a physics course, im really lost.
My physics is quite rusty but I believe that would be
V^2 = Vo^2 + 2ax
V^2 will be zero at the top since eventually the pull of gravity will stop the balls upward flight.
0 = (40 m/s)^2 + 2*(-9.8)*x
Solve for x = distance in meters.
alright, thanks lol