CALCULUS
posted by MATH .
Find a formula for the inverse of the function.
y=x^2x, x>=(greater than or equal to) 1/2
Please give me a step by step explanation. I think my algebra is wrong... Ty

x = y^2  y
y^2  y + 1 = x + 1
(y1)^2 = x + 1
y 1 = sqrt (x+1)
y = 1 + sqrt (x+1) 
noticed an error from line 2 to line 3
y^2  y = x
y^2  y + 1/4 = x + 1/4
(y  1/2)^2 =(4x+1)/4
y  1/2 = ±√(4x+1)/2
y = 1/2 ± √(4x+1)/2
= (1 ± √(4x+1) )/2 , x ≥ 1/4 
Whoops !

I don't understand. Why are you adding 1/4? to both sides? I don't see how you are getting a quadratic formula from this. More importantly, thank you guys for the help!