Posted by **Teddy** on Friday, January 31, 2014 at 10:19pm.

A projectile is launched from ground level at 37.0 m/s at an angle of 30.6 ° above horizontal. Use the launch point as the origin of your coordinate system.

a)How much time elapses before the projectile is at a point 8.9 m above the ground and heading downwards toward the ground?

b)How far downrange (the horizontal distance from the origin) was the projectile when it reached the highest point in its flight?

- physics -
**bobpursley**, Friday, January 31, 2014 at 10:52pm
hf=hi+vi*t-4.9t^2 vi= 37.0*sin30.6 hf=8.9 hi=0 solve for time t.

YOu get two solutions, take the largest time, it is going down then.

Highest point? Vvertical=0

Vv=0=vi*t-4.9t^2 vi = 37*sin30.6

solve for time t.

then horizontal distce= 37cos30.6*time

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