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March 6, 2015

March 6, 2015

Posted by **hajja** on Friday, January 31, 2014 at 10:04pm.

- integral calculus -
**Steve**, Friday, January 31, 2014 at 10:56pmIf you mean

∫[x,4] x/(x-4) dx

that's a bit unusual to have the variable of integration as one of the limits. But ok, let's work it out as-is.

∫x/(x-4) dx = x + 4 log(x-4)

Evaluating that at 4 and x, we have

(4+4log(0))-(x+4log(x-4))

Looks like -∞ to me. That upper limit of 4 is a killer

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