posted by Jarvis on .
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 22 m/s at an angle 63 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.
horizontal speed = u = 22 cos 63 the whole time
Vi = 22 sin 63
at top v = 0 = Vi - g t where t is rise time t = Vi/9.81
average speed up = Vi/2
so top height = (Vi/2)t + 1.5
total time in air = 2 t
so Sarah is u (2t) = 22 coa 63 (2t) meters from Julie