If a 65 kilogram load was raised 6 meters in 60 seconds determine the minimum rated wattage of the motor needed to accomplish this assuming the motor is 75% efficient. give your answer in W.
F = 65 * 9.81 Newtons
energy = F*d = 65*9.81*6 Joules
energy/unit time = power = 65*9.81*6/60 watts
divide by .75
65*9.81*6/(60*.75)
thanks so much!!!
You are welcome !
Well, let me calculate this for you using my specially programmed funny formula!
So, we have a load of 65 kilograms being raised 6 meters in 60 seconds. Now, if we want to determine the minimum rated wattage of the motor, we need to take into account the efficiency.
But before we do that, let me tell you a joke to lighten the mood. Why don't scientists trust atoms?
Because they make up everything!
Now back to the calculation. Since the motor is 75% efficient, we need to factor that in. So, the actual power output of the motor would be 75% of the required power.
Now, drum roll please... considering my calculations and the efficiency, the minimum rated wattage of the motor needed to accomplish this would be:
65 kg * 9.8 m/s^2 * 6 m / (60 s * 0.75)
And the answer is... ta-da! A whopping wattage of [calculate] W!
Remember, though, this is just a minimum estimation. It's always good to have a little extra power in reserve, you never know when you might need it. Just like having an extra joke to make someone smile!
To determine the minimum rated wattage of the motor needed to raise a 65 kilogram load 6 meters in 60 seconds, we need to consider the work done, efficiency, and time taken.
First, let's calculate the work done. The work done is given by the formula:
Work = Force × Distance
The force required to lift the load is equal to its weight. Weight, in this case, is the mass multiplied by the acceleration due to gravity (9.8 m/s^2). Therefore:
Force = Mass × Acceleration due to gravity
Force = 65 kg × 9.8 m/s^2 = 637 N
Next, we need to calculate the amount of work done in raising the load:
Work = Force × Distance
Work = 637 N × 6 m = 3822 Joules
Since work is equal to power multiplied by time, we can determine the power (wattage) required using this equation:
Power = Work / Time
Power = 3822 J / 60 s = 63.7 W
However, the motor is stated to be 75% efficient. This means that only 75% of the input power is converted into useful output power, while the rest is lost as heat or other inefficiencies.
To account for the motor's efficiency, we need to divide the required power by the efficiency:
Minimum Rated Wattage = Power / Efficiency
Minimum Rated Wattage = 63.7 W / 0.75 = 85.07 W
Therefore, the minimum rated wattage of the motor needed to accomplish this task, assuming a 75% efficiency, is 85.07 Watts.