How much (in Celsius degrees) is the temperature of 1.3 kg of alcohol raised by adding 4.1 kcal of heat? The following piece of information may come in handy: specific heat of alcohol is 0.58 kcal/kgC.
To calculate the increase in temperature of 1.3 kg of alcohol after adding 4.1 kcal of heat, we can use the formula:
Q = mcΔT
Where:
Q = heat energy (in kcal)
m = mass of the substance (in kg)
c = specific heat capacity of the substance (in kcal/kg°C)
ΔT = change in temperature (in °C)
Rearranging the formula to solve for ΔT:
ΔT = Q / (mc)
Now, let's substitute the given values into the formula:
Mass of alcohol (m) = 1.3 kg
Specific heat of alcohol (c) = 0.58 kcal/kg°C
Heat added (Q) = 4.1 kcal
ΔT = 4.1 kcal / (1.3 kg * 0.58 kcal/kg°C)
ΔT = 4.1 kcal / 0.754 kg°C
ΔT ≈ 5.43 °C
Therefore, the temperature of 1.3 kg of alcohol will be raised by approximately 5.43 °C when 4.1 kcal of heat is added.