How much heat is evolved when 500kg of Ammonia is evolved according to the following equation: N2(g)+3H2(g)<->2NH3(g) [deltaH =-91.8K]

To calculate the amount of heat evolved when 500 kg of ammonia is formed, first, we need to determine the number of moles of ammonia present in 500 kg.

We can use the following relation:
1 mole of NH₃ = 17.031 g

Thus, the number of moles of NH₃ can be calculated using the formula:
moles of NH₃ = mass of NH₃ / molar mass of NH₃

The molar mass of NH₃ is:
molar mass of NH₃ = 14.01 g/mol (molar mass of nitrogen) + 3 * (1.01 g/mol) (molar mass of hydrogen) = 17.031 g/mol

Substituting the values, we have:
moles of NH₃ = 500,000 g / 17.031 g/mol = 29,335.294 moles

According to the equation: N₂(g) + 3H₂(g) ↔ 2NH₃(g), we can see that the stoichiometric ratio of NH₃ to ΔH is 2:1.

Therefore, to find the heat evolved when 29,335.294 moles of NH₃ are formed, we can multiply it by the ΔH value.

Heat evolved = Moles of NH₃ * ΔH
Heat evolved = 29,335.294 moles * -91.8 kJ/mol

Calculating this value, we get:
Heat evolved = -2,691,758.82 kJ

Therefore, when 500 kg of ammonia is formed, approximately -2,691,758.82 kJ of heat is evolved.

To determine the amount of heat evolved when 500 kg of ammonia is formed, we need to use the equation provided and the corresponding enthalpy change (ΔH) value:

N2(g) + 3H2(g) ↔ 2NH3(g) ΔH = -91.8 kJ

First, we need to convert the given mass from kilograms to moles. To do this, we will use the molar mass of ammonia (NH3).

Molar mass of NH3:
1 mole of N = 14.01 g
3 moles of H = 3 × 1.01 g = 3.03 g

Molar mass of NH3 = 14.01 g + 3.03 g = 17.04 g/mol

Now we can calculate the number of moles of NH3 in 500 kg using the molar mass and Avogadro's number:

1 kg = 1000 g
500 kg = 500 × 1000 g = 500,000 g

Number of moles of NH3 = (500,000 g) / (17.04 g/mol)

Next, we can use the stoichiometry of the balanced equation to find the number of moles of N2 and H2 used:

From the balanced equation: N2(g) + 3H2(g) ↔ 2NH3(g)

For every 2 moles of NH3 formed, we need 1 mole of N2 and 3 moles of H2.

Number of moles of N2 = (Number of moles of NH3) / 2
Number of moles of H2 = 3 × (Number of moles of NH3)

Now that we have the number of moles for each component, we can calculate the heat evolved using the equation:

Heat evolved = (Number of moles of NH3) × (ΔH)

Substitute the values obtained:

Heat evolved = (Number of moles of NH3) × (-91.8 kJ)

Calculating all the values will give you the amount of heat evolved when 500 kg of ammonia is formed.

-91.8 kJ x (500/28) = -?