the perimeter of a rectangular garden is 40 meters. the length of the garden is 1 meter less than twice its with. what are the dimensions of the garden?

L = 2W - 1

2L + 2W = 40

Substitute 2W-1 for L in second equation and solve for W. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation.

Perimeter = The sum of all the sides (all the side lengths added together)

wait elina how do you solve it

To find the dimensions of the rectangular garden, we can set up a system of equations using the given information.

Let's assume the width of the garden is "w" meters.

According to the problem, the length of the garden is 1 meter less than twice its width. So, the length can be expressed as (2w - 1) meters.

The perimeter of a rectangle is given by the formula:
Perimeter = 2 * (length + width)

Given that the perimeter is 40 meters, we can write the equation as:
40 = 2 * ((2w - 1) + w)

Simplifying the equation:
40 = 2(3w - 1)
40 = 6w - 2
6w = 40 + 2
6w = 42
w = 42 / 6
w = 7

So, the width of the garden is 7 meters.
To find the length, we substitute the value of width (w) back into the equation:
length = 2w - 1
length = 2 * 7 - 1
length = 14 - 1
length = 13

Therefore, the dimensions of the rectangular garden are width = 7 meters and length = 13 meters.