How much time is needed for a car to accelerate from 8.0 m/s to speed of 22 m/s if the acceleration is 3.0 m/s^2?
acceleration= changevelocity/time
time= changevelocity/accel=14/3 seconds
To calculate the time it takes for a car to accelerate from an initial velocity (8.0 m/s) to a final velocity (22 m/s) with an acceleration of 3.0 m/s^2, you can use the following equation:
vf = vi + at
Where:
- vf is the final velocity
- vi is the initial velocity
- a is the acceleration
- t is the time
Rearranging the equation to solve for time (t), we have:
t = (vf - vi) / a
Substituting the given values:
t = (22 - 8) / 3
Calculating:
t = 14 / 3
Simplifying the fraction:
t ≈ 4.67 seconds
Therefore, it will take approximately 4.67 seconds for the car to accelerate from 8.0 m/s to a speed of 22 m/s.
To find the time needed for a car to accelerate from an initial velocity of 8.0 m/s to a final velocity of 22 m/s with an acceleration of 3.0 m/s^2, we can use the following kinematic equation:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Rearranging the equation, we have:
t = (v - u) / a
Substituting the given values:
t = (22 m/s - 8.0 m/s) / 3.0 m/s^2
t = 14 m/s / 3.0 m/s^2
Now, divide the units:
t = 14 / 3 s
Therefore, the time required for the car to accelerate from 8.0 m/s to a speed of 22 m/s with an acceleration of 3.0 m/s^2 is approximately 4.67 seconds.