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January 31, 2015

January 31, 2015

Posted by **NADIA** on Tuesday, January 28, 2014 at 1:06am.

an is sn=(3n-2)/(n+1)

what is an when x>1?

and what is the sum of an?

- calculus -
**Steve**, Tuesday, January 28, 2014 at 5:08amI assume that Sn = sum(1..n) An, so Sn -> 3

Dunno where the x comes from, but if you mean when n > 1,

An = Sn - s(n-1)

= (3n-2)/(n+1) - (3(n-1)-2)/(n-1+1)

= 5 / n(n+1)

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