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March 31, 2015

March 31, 2015

Posted by **Lynn** on Sunday, January 26, 2014 at 3:37am.

- trig -
**Steve**, Sunday, January 26, 2014 at 6:46amsolve the problem for a person of height zero, then add 5 feet to the answer. Also assume his eyes are on the top of his head.

If he starts at distance x, and the tower has height h, then

h/x = tan 30

h/(x-425) = tan 58

eliminate x to get

h/tan30 = h/tan58 + 425

now just solve for h.

- trig -
**Hussein**, Sunday, January 26, 2014 at 6:50amThis is easy problem if you draw the triangles properly.

If we consider the height of the tower above the person to be x and the distance remaining to reach the tower from where he made the last measurement to be y then

tan 32 = y/x

0.625 = y/x

x = y/0.625 = 1.6 y

but we also know from the larger triangle (the starting point) that

tan 30 = x/(425+y)

0.577 = x/(425+y)

x = 245.37 + 0.577 y

substitute from first equation into second one

1.6 y = 245.37 + 0.577 y

1.023 y = 245.37

y = 245.37/1.023= 239.85 feet

x = 1.6 * 239.85 = 383.76 feet

the height of the tower = 5 + 383.76= 388.76 feet

- trig -
**Lynn**, Sunday, January 26, 2014 at 11:47amThank you so much for the help.

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