A metal sphere is insulated electrically and is given a charge. If 50 electrons are added to the sphere in giving a charge, how many Coulombs are added to the sphere?
This question essentially comes down to how many Coulombs of charge 50 electrons have (i.e., the sphere, the initial charge, etc., are irrelevant). So, knowing that one elementary charge is
e = 1.6×10^-19 C
and that 50 electrons will have a total charge of -50e,
-50e × (1.6×10^-19 C/e) = -8.0×10^-18 C
The charge of an electron is approximately -1.6 x 10^-19 Coulombs. Since 50 electrons are added to the sphere, the total charge added can be calculated by multiplying the charge of one electron by the number of electrons added:
Total charge added = (Charge per electron) x (Number of electrons added)
= (-1.6 x 10^-19 C) x (50)
= -8.0 x 10^-18 C
Therefore, 8.0 x 10^-18 Coulombs are added to the sphere.
To determine the number of Coulombs added to the sphere, we need to know the charge of a single electron and its relationship to Coulombs.
The elementary charge, represented by the symbol "e," is the charge of a single electron. It is approximately equal to 1.602 x 10^-19 Coulombs.
Given that 50 electrons are added to the sphere, we can calculate the total charge added by multiplying the number of electrons by the charge of a single electron:
Total charge added = Number of electrons x Charge of a single electron
Total charge added = 50 electrons x (1.602 x 10^-19 Coulombs/electron)
Now we can calculate the answer.