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March 28, 2015

March 28, 2015

Posted by **NADIA** on Thursday, January 23, 2014 at 6:42pm.

cated at <94m, 0 m, 30m> and has momentum

<4500 kg · m/sec, 0 kg · m/sec,−3000 kg · m/sec> .

The car’s momentum is not changing. At time

18 s, find the position of the car:

~d = <dx, dy, dz>

- Physics -
**Damon**, Thursday, January 23, 2014 at 8:27pmconstant velocity components

Vx = 4500/1400

Vy = 0

Vz = -3000/1400

goes for 18-9 or 9 seconds

distance = speed*time

so

x = 94 + 9*4500/1400

y = 0 + 0

z = 30 -9(3000/1400)

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