How to solve d(d^-2)^-9? Please show and explain step-by-step.
What do you have to solve exactly? Do you by chance mean simplify?
Should there be an equal sign in the expression that you typed?
Simplify, sorry. The answer says d^19, but I don't get how.
d^1 * d^(-2*-9)
= d^1 * d^+18
= d^19
Thanks. Another one:
(z^8)^0 z^5
ANYTHING AT ALL^0 = ONE
so
z^5
To solve the expression d(d^-2)^-9, we need to follow the order of operations and simplify it step-by-step. Let's break it down:
Step 1: Simplify the innermost exponent.
d^-2 means the reciprocal of d squared, which is equal to 1/d^2.
So, the expression becomes d(1/d^2)^-9.
Step 2: Apply the negative exponent.
When we have a negative exponent, we can rewrite it as the reciprocal with the positive exponent. In this case, the negative exponent is -9:
d(1/d^2)^-9 = d/d^18.
Step 3: Simplify the expression further.
Now, we multiply d by the reciprocal of d^18. Note that when we divide by a fraction, we multiply by its reciprocal. Thus, we can rewrite it as:
d/d^18 = d * (1/d^18) = 1/d^17.
The final result is 1/d^17.
In summary, to solve the expression d(d^-2)^-9:
1. Simplify the innermost exponent to 1/d^2.
2. Apply the negative exponent to get 1/d^18.
3. Simplify further to the final answer of 1/d^17.