Physics
posted by Sandara on .
A tennis ball is thrown up with an initial speed of 22.5m/s. It is caught at the same distance above the ground.
A) how high does the ball rise
B) how long does the ball remain in the air?

initial KE=final PE
1/2 m 22.5^2=m g h
solve for h.
time in air:
hf=hi+vi*t4.9t^2
hf=hi and vi is given, solve for t.