A rock is dropped from rest. How fast is it going after it has been falling for 8.3 s?

v=g*time

so 81.34?

To determine how fast the rock is going after it has been falling for 8.3 seconds, we can use the equation for the velocity of a falling object.

The equation for the velocity of a falling object is given by:

v = gt

Where:
v is the final velocity (speed) of the object
g is the acceleration due to gravity, which is approximately 9.8 m/s^2
t is the time the object has been falling

In this case, we are given that the rock has been falling for 8.3 seconds, so we can substitute this value in the equation:

v = (9.8 m/s^2) x (8.3 s)

Now, let's solve the equation:

v = 81.34 m/s

So, the rock is going approximately 81.34 meters per second after it has been falling for 8.3 seconds.