The image on a movie poster was shrunk to make the DVD cover art for the movie, so that the cover art is a scale image of the poster. The poster is 36 inches wide, and the DVD cover art is 6 inches wide. If the diagonal of the poster is 4.5 feet, what is the diagonal of the DVD cover art?
12 inches
9 inches
0.67 inch
7 inches
ANY LENGTH on the DVD cover is (1/6) of the SIMILAR measure on the poster.
4.5 ft * 12 in/ft = 54 inches on the poster
then
54/6 = 9 inches on the DVD
posterwide/dvdwide=posterdiagonal/dvddiagonal
36/6=4.5/dvdwide
divdwide= 4.5*6/36
thanks Damon ฅ^•ﻌ•^ฅ
I had the same question
To solve this problem, let's use the concept of similar triangles.
First, we need to find the scale factor by comparing the width of the poster to the width of the DVD cover art. The scale factor is calculated by dividing the width of the DVD cover (6 inches) by the width of the poster (36 inches).
The scale factor is 6/36, which simplifies to 1/6.
Now, we will use the scale factor to find the diagonal of the DVD cover art. Since the scale factor applies to all dimensions (length, width, and diagonal) equally, we multiply the scale factor by the diagonal of the poster.
The diagonal of the poster is given as 4.5 feet, which is 4.5 * 12 = 54 inches.
Multiplying the scale factor (1/6) by the diagonal of the poster (54 inches) gives us the diagonal of the DVD cover art.
(1/6) * 54 = 9 inches.
Therefore, the diagonal of the DVD cover art is 9 inches.
So, the correct answer is: 9 inches.