Chemistry Help Please!
posted by Josh on .
An industrial chemist puts 1.00 mol each of H2(g) and CO2(g) in a 1.00-L container at 800oC. When equilibrium is established, 0.49 mol of CO(g) is in the container. Find Kc at 800 C for the following reaction:
H2(g) + CO2(g) ⇌ H2O(g) + CO(g).
H2 + CO2 <> H2O + C0 all gases.
K= (.49)^2 /(1-.49)(1-.49)=(.49/.51)^2
check my work