Posted by Anonymous on .
What is the simplified form of 3a^4b^2c^3?
a. (81a^4c^3)/(b^2)
b. (81a^4)/(b^2c^3)
c. (3a^4)/(b^2c^3)
d. (3a^4c^3)/(b^2)
D
What is a^2 if a = 5?
a. 25
b. 25
c. 1/25
d. 1/25
D
What is (m)^3n if m = 2 and n = 24?
a. 3
b. 3
c. 4
d. 4
A

Algebra Check 
Damon,
What is the simplified form of 3a^4b^2c^3?
a. (81a^4c^3)/(b^2)
b. (81a^4)/(b^2c^3)
c. (3a^4)/(b^2c^3)
d. (3a^4c^3)/(b^2)
D YES
What is a^2 if a = 5?
a. 25
b. 25
c. 1/25
d. 1/25
D No 1/(5)^2 = 1/25 so C
What is (m)^3n if m = 2 and n = 24?
a. 3
b. 3
c. 4
d. 4
A NONE OF THESE. 2^72 is huge. You have a TYPO 
Algebra Check 
Anonymous,
It is not 3n. It is (m)^3 n. So it would be .125* 24, which is how I did it.

Algebra Check 
Damon,
[(m)^3 ] n
[1/(2)^3] (24)
(1/8)(24)
3
YES A 
Algebra Check 
Anonymous,
Thank you so much! Just one quick question...is it a rule to always simplify first and then substitute, as in question 2?

Algebra Check 
Damon,
That is up to you.

Algebra Check 
person,
Are all of these correct Damon?

Algebra Check 
hi,
all of Damon's answers are correct