Half of Henry’s age added to 13 of Daisy’s age is 11 years. Six years from now, the sum of their ages will
be 40 years. How old is each six years from now?
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To solve this problem, we can use algebraic equations.
Let's assume Henry's current age is H and Daisy's current age is D.
According to the first statement, half of Henry’s age added to 13 of Daisy’s age is 11 years. We can write this as the equation:
(H/2) + 13 = 11
Simplifying this equation, we get:
H/2 = 11 - 13
H/2 = -2
Multiplying both sides by 2, we obtain:
H = -4
But since age cannot be negative, we know there must be a mistake or inconsistency in the information provided. Please double-check the problem statement for accuracy.