Ayie is 7 years older than Luis. Next year, she will be 1 year more than twice as old as he will be. How old is she now?
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To determine Ayie's current age, we can work through the problem step by step.
Let's assume that Luis is X years old.
According to the problem, Ayie is 7 years older than Luis, so Ayie's age can be represented as X + 7.
Next year, Ayie will be 1 year more than twice as old as Luis will be:
Ayie's age next year (X + 1 + 7) will be equal to twice Luis's age next year (2 * (X + 1)) plus 1.
Now we can set up an equation to represent the problem:
X + 1 + 7 = 2 * (X + 1) + 1
Let's solve the equation:
X + 8 = 2X + 2 + 1
X + 8 = 2X + 3
X - 2X = 3 - 8
-X = -5
X = 5
Therefore, Luis is currently 5 years old.
Ayie's age can be calculated using the equation: Ayie's age = X + 7
Ayie's age = 5 + 7
Ayie is currently 12 years old.