Posted by Nicole Faith on .
Ten years ago a man was three times as old as his son. In twelve more years,the son is three fifths as old as his father.what were their ages 5 years ago?

Algebra 
Reiny,
10 years ago:
son  x
father  3x
NOW:
son  x+10
father  3x+10
12 years from now:
son  x+22
father  3x + 22
x+22 = (3/5)(3x + 22)
times 5
5x + 110 = 9x + 66
4x = 44
x = 11
so 5 years ago:
son = present age  5
= (11+10)  5 = 16
father = 3x+10  5 = 38
So 5 years ago, the son was 16, and the father was 38
(right now the son is 21, and the father is 43)