Wednesday

October 22, 2014

October 22, 2014

Posted by **NADIA** on Sunday, January 19, 2014 at 9:07pm.

<0.02m, 0.04m,−0.06m>, and 4 μs later is de-

tected at location <0.02 m, 1.84 m,−0.86 m>.

Find the average velocity of the elecron:

Żv = <vx, vy, vz>

If the electron continues to travel at this av-

erage velocity, find where it will be in another

9 μs :

~d = <dx, dy, dz>

Answer in units of m

I've tried this question several times and I cannot get the second part correct.

For the first part I get <0, 450000, -200000>

But then for the second part I keep getting it wrong. for dx i get 0 which is correct, but for dy= .04+(5 * 450000) it says it's wrong. not sure what im doing wrong!

**Answer this Question**

**Related Questions**

physics - An electron passes location h0.02m, 0.04m,−0.06mi, and 4 μs...

biology - Given the part of the molecule shown below, can the underlined atom ...

Calc - Recall that the average velocity between times t1and t2 is calculated ...

Calculus - Recall that the average velocity between times t1and t2 is calculated...

physics - The area shown is the boundary of a magnetic ﬁeld directed in ...

Physics-friction problem - A 0.170 kg hockey puck is initially moving at 21.2 m/...

chemistry - For which of these elements would the electron affinity process ...

chemistry - For which of these elements would the electron affinity process ...

Statistics - A sample of 11 observations taken from a normally distributed ...

physics - An electron in an electron beam experiences a downward force of 1.9×10...