Posted by
**NADIA** on
.

An electron passes location

<0.02m, 0.04m,−0.06m>, and 4 μs later is de-

tected at location <0.02 m, 1.84 m,−0.86 m>.

Find the average velocity of the elecron:

¯v = <vx, vy, vz>

If the electron continues to travel at this av-

erage velocity, find where it will be in another

9 μs :

~d = <dx, dy, dz>

Answer in units of m

I've tried this question several times and I cannot get the second part correct.

For the first part I get <0, 450000, -200000>

But then for the second part I keep getting it wrong. for dx i get 0 which is correct, but for dy= .04+(5 * 450000) it says it's wrong. not sure what im doing wrong!