Friday
March 24, 2017

Post a New Question

Posted by on Sunday, January 19, 2014 at 8:48pm.

An electron passes location
h0.02m, 0.04m,−0.06mi, and 4 μs later is de-
tected at location h0.02 m, 1.84 m,−0.86 mi.
Find the average velocity of the elecron:
¯v = <vx, vy, vz>

If the electron continues to travel at this av-
erage velocity, find where it will be in another
9 μs :
~d = <dx, dy, dz>

Answer in units of m

  • physics - , Sunday, January 19, 2014 at 8:51pm

    dx=(xf-xi)

    vx=dx/dt=dx/4E-6

    similarlly, vy, vz.

    then for the second part, knowing the velocities

    xf=xi+vx*dt

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question