Posted by **NADIA** on Sunday, January 19, 2014 at 8:48pm.

An electron passes location

h0.02m, 0.04m,−0.06mi, and 4 μs later is de-

tected at location h0.02 m, 1.84 m,−0.86 mi.

Find the average velocity of the elecron:

¯v = <vx, vy, vz>

If the electron continues to travel at this av-

erage velocity, find where it will be in another

9 μs :

~d = <dx, dy, dz>

Answer in units of m

- physics -
**bobpursley**, Sunday, January 19, 2014 at 8:51pm
dx=(xf-xi)

vx=dx/dt=dx/4E-6

similarlly, vy, vz.

then for the second part, knowing the velocities

xf=xi+vx*dt

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