Posted by **NADIA** on Sunday, January 19, 2014 at 8:48pm.

An electron passes location

h0.02m, 0.04m,−0.06mi, and 4 μs later is de-

tected at location h0.02 m, 1.84 m,−0.86 mi.

Find the average velocity of the elecron:

Żv = <vx, vy, vz>

If the electron continues to travel at this av-

erage velocity, find where it will be in another

9 μs :

~d = <dx, dy, dz>

Answer in units of m

- physics -
**bobpursley**, Sunday, January 19, 2014 at 8:51pm
dx=(xf-xi)

vx=dx/dt=dx/4E-6

similarlly, vy, vz.

then for the second part, knowing the velocities

xf=xi+vx*dt

## Answer This Question

## Related Questions

- Physics - An electron passes location <0.02m, 0.04m,−0.06m>, and 4...
- Calculus - A pharmaceutical corporation has two locations that produce the same ...
- physics - (a) Find the electric potential difference V B − V A due to a ...
- physics - The area shown is the boundary of a magnetic ﬁeld directed in ...
- Calc - Recall that the average velocity between times t1and t2 is calculated ...
- Calculus - Recall that the average velocity between times t1and t2 is calculated...
- biology - Given the part of the molecule shown below, can the underlined atom ...
- Physics-friction problem - A 0.170 kg hockey puck is initially moving at 21.2 m/...
- calculus - When a ball is thrown vertically upward into the air with a velocity ...
- chemistry - For which of these elements would the electron affinity process ...

More Related Questions