physics
posted by NADIA on .
An electron passes location
h0.02m, 0.04m,−0.06mi, and 4 μs later is de
tected at location h0.02 m, 1.84 m,−0.86 mi.
Find the average velocity of the elecron:
¯v = <vx, vy, vz>
If the electron continues to travel at this av
erage velocity, find where it will be in another
9 μs :
~d = <dx, dy, dz>
Answer in units of m

dx=(xfxi)
vx=dx/dt=dx/4E6
similarlly, vy, vz.
then for the second part, knowing the velocities
xf=xi+vx*dt