In a combustion reaction, propane (C3H8) reacts with oxygen. How many moles of CO2 can be produced when 2.25 mol of C3H8 react?
C3H8(g) + 5O2(g) -„³ƒn3CO2(g) + 4H2O(g)
To determine the number of moles of CO2 that can be produced when 2.25 mol of C3H8 react, we need to use the balanced equation for the combustion reaction:
C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(g)
From the balanced equation, we can see that for every 1 mole of C3H8, 3 moles of CO2 are produced. Therefore, to find the number of moles of CO2 produced when 2.25 mol of C3H8 react, we can set up a proportion:
(2.25 mol C3H8) / (1 mol C3H8) = (x mol CO2) / (3 mol CO2)
Simplifying the proportion, we get:
2.25 mol C3H8 = (x mol CO2) / 3
To solve for x (the number of moles of CO2), we can multiply both sides of the equation by 3:
2.25 mol C3H8 * 3 = x mol CO2
x = 6.75 mol CO2
Therefore, when 2.25 mol of C3H8 react, 6.75 mol of CO2 can be produced.