3. Which of the following equations has an infinite number of solutions? (1 point)

a. 3x – 3 = –4x
b. 2y + 4 – y = 16
c. 7x + 5 = 4x + 5 + 3x
d. 6y – 2 = 2(y – 1)

IS THE ANSWER A??!!!

oh, ok thanx

(sry for the caps, i didn't know they were on)

no the answer should be C

To determine which of the equations has an infinite number of solutions, we need to solve each equation and see if we end up with a true statement, such as 0 = 0, or if the unknown variable cancels out completely.

a. 3x - 3 = -4x:
Let's simplify the equation by moving all the terms with x to one side:
3x + 4x = 3
7x = 3
x = 3/7

Since x has a specific value, this equation has a unique solution, not an infinite number of solutions.

b. 2y + 4 - y = 16:
Combine like terms:
y + 4 = 16
Subtract 4 from both sides:
y = 12

Similar to the previous equation, this equation has a specific solution, not an infinite number of solutions.

c. 7x + 5 = 4x + 5 + 3x:
Combine like terms:
7x = 7x + 10
Subtract 7x from both sides:
0 = 10

Here, we end up with a false statement, 0 = 10. This implies that the left-hand side (LHS) and right-hand side (RHS) of the equation are not equal for any value of x. Therefore, this equation has no solution, not an infinite number of solutions.

d. 6y - 2 = 2(y - 1):
Expand the brackets:
6y - 2 = 2y - 2
Subtract 2y from both sides:
4y - 2 = -2
Add 2 to both sides:
4y = 0
Divide by 4:
y = 0

Here, we find a specific value for y, not an infinite number of solutions.

Since option a, 3x - 3 = -4x, is the only equation that has a unique solution, the correct answer is NOT a.