A carpenter has several boards of equal length. He cuts 3/5 of each board. After cutting the boards, the carpenter notices that he has enoughpieces left over to make uo the same length as 4 of the original boards. How many boards did the carpenter start with?

To solve this problem, we can use algebraic equations. Let's assign a variable to represent the number of boards the carpenter started with. Let's call this variable "x".

The length of each original board is the same. Let's say the length of each board is "L".

The carpenter cuts 3/5 of each board, so the length of each cut piece is (3/5) * L.

After cutting the boards, the carpenter notices that he has enough pieces left over to make up the same length as 4 of the original boards. Therefore, we can set up the equation:

(3/5) * L * x = L * 4

Now, we can simplify the equation:

(3/5) * x = 4

To solve for x, we can multiply both sides of the equation by (5/3):

(5/3) * (3/5) * x = (5/3) * 4

x = 20/3

Since the number of boards must be a whole number, we need to round the answer. Rounding up, we find that the carpenter started with approximately 7 boards.