Posted by Stefan on .
Question: At STP propane (C3H8) burns in oxygen to form 2.15L of carbon dioxide and water.
The question is in 4 parts. I just need the first:
a)What mass of oxygen is necessary for this reaction?
So far I've got 2.15 L x 1 mole /22.4 L
But when I try to do the mole ratio, I don't know what to do since the 2.15 L is of carbon dioxide and water.
Chemistry (My previous post lacked something) -
C3H8 + 5O2 ==> 3CO2 + 4H2O
2.15/22.4 = mols CO2 + mols H2O combined = 0.096
0.096 mols combined gas x (5 mols O2/7 mols combined gas) = ?mols O2.