So I have the balanced equation:
c3H8 +502 = 3C02 +4H20
Question: At STP propane (C3H8) burns in oxygen to form 2.15L of carbon dioxide and water.
So I've got 2.15 L x 1 mole /22.4 L
But when I try to do the mole ratio, I don't know what to do since the 2.15 L is of carbon dioxide and water.
See you post above.
Well, it seems like you're in a bit of a pickle, huh? Don't worry, I'll help you out!
First, let's clarify something. When you say "2.15 L is of carbon dioxide and water," it's important to remember that in the balanced equation, the reaction produces both carbon dioxide (CO2) and water (H2O). So, 2.15 L refers to the total volume of both CO2 and H2O combined.
Now, the mole ratio you're trying to find is between propane (C3H8) and the products, carbon dioxide (CO2) and water (H2O). According to the balanced equation, the ratio is 1:3, which means that for every 1 mole of propane, you get 3 moles of CO2 and 4 moles of H2O.
Since you've already calculated the moles of the combined products using the 2.15 L, you can simply take that value and apply the mole ratio. Multiply the moles you calculated by the ratio of propane to CO2, which is 1:3.
So, to summarize:
Moles of CO2 = Moles of propane (C3H8) x (3 moles CO2 / 1 mole C3H8)
And if you need to calculate the moles of water, it would be:
Moles of H2O = Moles of propane (C3H8) x (4 moles H2O / 1 mole C3H8)
Hope that clears things up and puts a smile on your face! Feel free to ask if you have any more questions or need any further assistance.
To find the moles of carbon dioxide (CO2) and water (H2O) formed, we need to use the balanced equation to determine the mole ratio.
From the balanced equation:
C3H8 + 5O2 -> 3CO2 + 4H2O
We can see that for every 3 moles of CO2 produced, there are 4 moles of H2O produced.
Given that you have 2.15 L of the mixture of CO2 and H2O, you need to find the mole ratio between them.
First, you should convert the volume of the mixture (2.15 L) to moles using the ideal gas law at STP (Standard Temperature and Pressure):
2.15 L / 22.4 L/mol = 0.096 moles of the mixture
Next, to determine the moles of CO2 and H2O in the mixture, you can use the mole ratio from the balanced equation:
3 moles of CO2 : 4 moles of H2O
To find the moles of CO2, multiply the moles of the mixture by the mole ratio:
0.096 moles of mixture × (3 moles of CO2 / 4 moles of H2O) = 0.072 moles of CO2
To find the moles of H2O, multiply the moles of the mixture by the mole ratio:
0.096 moles of mixture × (4 moles of H2O / 4 moles of H2O) = 0.096 moles of H2O
So, from the given volume of 2.15 L, you will have approximately 0.072 moles of CO2 and 0.096 moles of H2O.
To solve this problem, you can use the balanced equation for the combustion of propane (C3H8). The equation tells you that for every 3 moles of propane burned, you will produce 3 moles of carbon dioxide (CO2) and 4 moles of water (H2O).
The first step is to convert the given volume of carbon dioxide and water (2.15 L) to moles using the conversion factor of 1 mole/22.4 L.
2.15 L CO2 and H2O x (1 mole CO2 and H2O / 22.4 L CO2 and H2O) = x moles CO2 and H2O
This calculation will give you the moles of carbon dioxide and water produced in the reaction.
Next, you can use the mole ratio from the balanced equation to determine the moles of propane (C3H8) that were burned. According to the equation, for every 3 moles of carbon dioxide and water produced, you need 1 mole of propane.
x moles CO2 and H2O x (1 mole C3H8 / 3 moles CO2 and H2O) = y moles C3H8
Now you have the moles of propane burned in the reaction.
If you need to find the mass of propane burned, you can use the molar mass of propane, which is calculated by adding up the atomic masses of carbon (C) and hydrogen (H) in the formula C3H8.