Posted by Andy G on Tuesday, January 14, 2014 at 6:29pm.
An open box with a volume of 1500cm^3 is to be constructed by taking a piece of cardboard of 20 cm by 40 cm, cutting squares of sides length x cm from each corner and folding up the sides. Show that this can be done in two different ways, and find exact dimensions of the box in each case.
I have already found the solution using the quadratic equation, can someone help me find the solution using synthetic division?

PreCalc  Damon, Tuesday, January 14, 2014 at 6:59pm
L = 40  2x
w = 20 2x
V = 1500 = L w x
1500= (402x)(202x)x = (800 120 x + 4 x^2)x
so
4x^3  120 x^2 + 800 x 1500 = 0
make a reasonable guess
x = 5 for example
then the box would be 30*10 * 5 = 1500
good, height of five is a solution
so divide by (x5)
x^3  120 x^2 + 800 x 1500

(x5)
= 4 x^2100 x +300
factor that
4 (x^2 25 x + 75) = 0
I get about 21 which is too big to take off the width and 2.89
check x = 2.89
20  5.78 = 14.22
40  5.78 = 34.22
v = 14.22*34.22*2.89 = 1406
well, better do it a bit more accurately
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