Posted by **Anonymous** on Tuesday, January 14, 2014 at 6:13pm.

How many solutions does this system of equations have?

y = 4x + 3 and 2y - 8x = 3

One, two, infinitely many, or no solutions? My answer is no solutions.

- Algebra -
**Damon**, Tuesday, January 14, 2014 at 6:16pm
y = 4 x + 3

y = 4 x + 3/2

two lines with the same slope but different y axis intercepts. They never cross each other and therefore there is no solution to this problem.

- Algebra -
**Anonymous**, Tuesday, January 14, 2014 at 6:24pm
Thanks. I have a couple more:

x = -4y + 4 and 2x + 8y = 8

Answer: Infinitely many solutions

x - 3y = 15 and 3x - 9y = 4

Answer: Infinitely many solutions

y - 5x = -6 and 3y - 15x = -12

Answer: One solution

- Algebra -
**Damon**, Tuesday, January 14, 2014 at 6:29pm
x - 3y = 15 and 3x - 9y = 4

x - 3 y = 4/3

Same slope, never cross NO solutions !

Answer: Infinitely many solutions DIASAGREE

y - 5x = -6 and 3y - 15x = -12

y - 5 x = -4

AGAIN, they are NOT the same. They are PARALLEL and never cross NO solutions

same m = slope = either the same (infinite solutions of parallel (different y intercept) which means ZERO solutions

Answer: One solution NO!

- Algebra -
**Anonymous**, Tuesday, January 14, 2014 at 6:40pm
Seems like both have no solutions. I went a bit off in my calculation. I see now.

- Algebra -
**Damon**, Tuesday, January 14, 2014 at 7:04pm
When in doubt, sketch a graph

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