Nila is now x years old. Three yrs ago, her brother ricky was twice as old as she, write rickys age ten yrs frm now in terms of x.
(With solution pls) tnx...
Nila's age = X yrs old, now.
Nila's age = (X-3) yrs old, 3 yrs ago.
Ricky's age = 2(X-3) yrs old, 3 yrs ago.
Ricky-Nila = 2(X-3)-(X-3) = (X-3) yrs
older than Nila.
Ricky's age, now = X + (X-3) = (2x-3)
yrs old.
Ricky's age 10 yrs from now = 10(2x-3) =
(20x-30) yrs old.
Correction:
Ricky's age 10 yrs from now =(2x-3)+10 =
2x+7.
2x+7
To solve this problem, we need to set up equations based on the information given.
Let's start by breaking down the information given:
1. Nila is now x years old.
2. Three years ago, Ricky was twice as old as Nila.
Let's represent Ricky's current age as R and Nila's current age as N:
1. We know that N = x (Nila's current age is x years old).
2. Three years ago, Ricky was twice as old as Nila, which can be expressed as: R - 3 = 2(N - 3).
Now, let's solve for R in terms of x:
1. Plugging in N = x into the equation R - 3 = 2(N - 3), we have R - 3 = 2(x - 3).
2. Expand the equation: R - 3 = 2x - 6.
3. Add 3 to both sides of the equation: R = 2x - 3.
So, Ricky's current age (R) in terms of x is: 2x - 3.
To find Ricky's age ten years from now, we add 10 to his current age:
Ricky's age ten years from now = (2x - 3) + 10 = 2x + 7.
Therefore, Ricky's age ten years from now can be expressed as 2x + 7.