a box contains 22 coins consisting of quarters and dimes. the total value of the coins is $3.55. determine the number of quarters and the number of dimes in the box?

Its 9 quarters and 13 Dimes your welcome.

To determine the number of quarters and dimes in the box, we can set up a system of equations based on the given information. Let's denote the number of quarters as Q and the number of dimes as D.

From the given information, we can establish two equations:

1. The total number of coins is 22:
Q + D = 22

2. The total value of the coins is $3.55:
0.25Q + 0.10D = 3.55

We can solve this system of equations using substitution or elimination.

Let's solve by elimination:
Multiplying the first equation by 0.10, we get:
0.10Q + 0.10D = 2.20

Subtracting this equation from the second equation, we can eliminate D:
(0.25Q + 0.10D) - (0.10Q + 0.10D) = 3.55 - 2.20
0.15Q = 1.35

Dividing both sides of the equation by 0.15:
Q = 1.35 / 0.15
Q = 9

Now substitute the value of Q back into the first equation to find D:
9 + D = 22
D = 22 - 9
D = 13

Therefore, there are 9 quarters and 13 dimes in the box.

15

5 quarters (1.25)+23 dimes(2.30)