math
posted by B8 on .
Jesse rents 2 movies and 4 video games for a total of $18.70. At the same time, Dan rents 3 movies and 2 video games for a total of $15.25.
How much does their friend Sabrina need to rent a combination of one game and one movie from the same video rental store?
SO I HAD V= VIDEO GAME RENTAL
m= movie rental
2m+4v=18.70
2(3m+2v=15.25)
2m+4v=18.70
6m4v=30.50
4m=11.8

4 4 dividing each side by 4
m=$2.95
Then 2m +4v =18.70
2(2.95)+4v =18.70
5.90+4v=18.70
5.90 5.90
4v=12.80

4 4 divide each side by 4
v=$3.20
2.95 +3.20=$6.15
the cost for one movie was $2.95, and the cost for one video game was $3.20. Sabrina would need a total of $6.15
Is this correct?
Thanks for checking over my work

CORRECT
OR
m = price of movies
v = price of video game
3 m + 2 v = 15.25

2 m + 4 v = 18.7
___________________
m  2 v =  3.45
m = 2 v  3.45
3 m + 2 v = 15.25
3 ( 2 v  3.45 ) + 2 v = 15.25
6 v  10.35 + 2 v = 15.25
6 v + 2 v = 15.25 + 10.35
8 v = 25.6
v = 25.6 / 8
v = 3.2 $
m = 2 v  3.45
m = 2 * 3.2  3.45
m = 6.4  3.45
m = 2.95 $
m + v = 2.95 + 3.2 = 6.15 $ 
Thank you