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Posted by ashley on Saturday, January 11, 2014 at 10:18pm.

A large pipe has a diameter of 9.8×10^2cm.Water flows in the pipe at a speed of 5m s^-1.Find the volume in m^3,of water that flows out from the pipe every second,correct to 2 significant fogures.[Take pai as 3.142]

9.8x10^2 cm = 980cm = 9.8m So, the rate of flow is pi*4.9^2 m^2 * 5m/s = 377 m^3/s

Steve,how to get 4.9?

Ohh..i got it..divide two..thanks a lot!

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