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March 4, 2015

March 4, 2015

Posted by **B8** on Saturday, January 11, 2014 at 9:29pm.

x+5+x+1+x=3(x+2)+1

1)x=0

2)x=3

3)no solution

4) infinite

I got #3 no solution

x+5+x+1+x=3(x+2)+1

x+5+x+1+x=3x+6+1

3x+6=3x+7

-3x -3x

6=7 so no solution

Is this correct?

Thanks for checking over my work.

- math -
**Reiny**, Saturday, January 11, 2014 at 9:35pmcorrect

If your x's drop out and you end up with a false statement, such as our 6 = 7, then there is NO solution

if, however, the x's drop out and you end up with a true statement, there would have been an infinite number of solutions.

- math -
**B8**, Saturday, January 11, 2014 at 9:41pmOK.

Thanks for the added information explaining how the answer could have been different.

Thank you for your help!

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