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December 22, 2014

December 22, 2014

Posted by **helen** on Saturday, January 11, 2014 at 8:30pm.

- algebra -
**Reiny**, Sunday, January 12, 2014 at 12:49amThe values that we need from Pascal's triangle are

1 5 10 10 5 1

(s+2v)^5

= s^5 + 5(s^4)(2v) + 10(s^3)(2v)^2 + 10(s^2)(2v)^3 + 5(s)(2v)^4 + (2v)^5

= ..

I will leave the algebraic simplification up to you

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