A satellite is placed in orbit 100 km above the surface of the earth (radius = 6370 km, mass = 5.98 x 1024 kg).

If the satellite has a mass of 1500 kg, what is the force of gravity acting on it?

Now I did g relative to g earth for someone a few minutes ago

http://www.jiskha.com/display.cgi?id=1389396878

so g out there = 9.81*6370^2/6470^2)
= 9.51 m/s^2
so
Fg = 1500 * 9.51
Fg = 14364 Newtons

now before you ask
F = m a
F/m = a = 9.51 = v^2/r
so v^2 = 9.51 r

=

To calculate the force of gravity acting on the satellite, we can use the formula:

F = (G * m1 * m2) / r^2

Where F is the force of gravity, G is the gravitational constant (approximately 6.67430 x 10^(-11) m^3 kg^(-1) s^(-2)), m1 and m2 are the masses of the two objects (in this case, the satellite and the Earth), and r is the distance between the centers of the two objects.

First, we need to calculate the distance between the centers of the satellite and the Earth. Since the satellite is placed 100 km above the surface of the Earth, we can add the radius of the Earth to the altitude of the satellite to find the total distance between their centers:

r = altitude + radius = 100 km + 6370 km = 6470 km = 6,470,000 meters

Next, we can plug the values into the formula:

F = (G * m1 * m2) / r^2

G = 6.67430 x 10^(-11) m^3 kg^(-1) s^(-2)
m1 = mass of the Earth = 5.98 x 10^24 kg
m2 = mass of the satellite = 1500 kg
r = 6,470,000 meters

Plug the values into the formula:

F = (6.67430 x 10^(-11) * 5.98 x 10^24 * 1500) / (6,470,000)^2

Now, we can calculate the force of gravity.