Which of the following equations has an infinite number of solutions?

3x ¨C 3 = ¨C4x
2y + 4 ¨C y = 16
7x + 5 = 4x + 5 + 3x
6y ¨C 2 = 2(y ¨C 1)

Write the inequality and solve for the following problem:

The result of 6 subtracted from a number n is at least 2.

n ¨C 2 > 6; n > 8
n ¨C 6 ¡Ý 2; n ¡Ý 8
n + 6 ¡Ý 2; n ¡Ü 4
n + 6 ¡Ý 2; n ¡Ý 4

Can someone plz help me?

If you mean

3x-3 = -4x
2y+4-y = 16
7x+5 = 4x+5+3x
6y - 2 = 2(y-1)

Then the 3rd one is the same on both sides, so it has many solutions. Any value of x will work.

n-6 >= 2

steve is right!!! :)))))

To determine which equation has an infinite number of solutions, we need to simplify each equation and see if there is a variable that cancels out.

1. Simplifying the equation 3x - 3 = -4x:
Add 4x to both sides: 3x + 4x - 3 = 0
Combine like terms: 7x - 3 = 0

2. Simplifying the equation 2y + 4 - y = 16:
Combine like terms: y + 4 = 16
Subtract 4 from both sides: y = 12

3. Simplifying the equation 7x + 5 = 4x + 5 + 3x:
Combine like terms: 7x + 5 = 7x + 5
Cancel out the 7x on both sides: 5 = 5
This equation is always true, indicating an infinite number of solutions.

4. Simplifying the equation 6y - 2 = 2(y - 1):
Distribute 2 to both terms inside the parentheses: 6y - 2 = 2y - 2
Subtract 2y from both sides: 6y - 2y - 2 = -2
Combine like terms: 4y - 2 = -2
Add 2 to both sides: 4y = 0
Divide both sides by 4: y = 0

From the simplifications, we can see that the equation 7x + 5 = 4x + 5 + 3x has an infinite number of solutions.

Now let's solve the inequality problem:

The result of 6 subtracted from a number n is at least 2.
To write the inequality, we can translate the phrase "at least 2" to "greater than or equal to 2".

1. Translate the given information into an equation: n - 6 ≥ 2
2. Solve for n by adding 6 to both sides: n ≥ 8

Therefore, the correct inequality and solution for the problem is n ≥ 8.