Posted by **Math** on Monday, January 6, 2014 at 7:21pm.

The area of a cylinder is 956m3. If the circular top is halved, what is the new volume?

- Math -
**Reiny**, Monday, January 6, 2014 at 8:26pm
Your question is rather vague.

When you say that the circular top is halved, are you taking half of the diameter or half of the area ?

- Math -
**Anonymous**, Monday, January 6, 2014 at 8:49pm
The radius is halved

- Math -
**Reiny**, Monday, January 6, 2014 at 9:19pm
(same as diameter halved, anyway ....)

original:

radius r, height h

surface area = 2πrh + 2πr^2

= 956

πrh + πr^2 = 478

h = (478-πr^2)/(πr)

for new cylinder, height = h, radius = r/2

volume = π(r^2/4)(478-πr^2)/(πr)

= (478r - πr^3)/4

so the relationship depends on the value of r

Are you sure the area was 956 and not the volume?

then the volume would simply be 1/4 of the original, or 239 m^3

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