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January 30, 2015

January 30, 2015

Posted by **jeremy steadman** on Monday, January 6, 2014 at 6:28pm.

- physics -
**Damon**, Monday, January 6, 2014 at 6:38pmwork = force * distance

= F d

F the same for both

work done = kinetic energy lost

= .5 m v^2

same m

V2 = 3 V1

so

V2^2 = 9 V1^2

so work done at 50 = (1/2)m V1^2 = F d1

and at 150 = (1/2) m (9 V1 ^2) = F d2

so

d2/d1 = 9

9 * 15 = 135

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