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February 28, 2015

February 28, 2015

Posted by **jeffery** on Monday, January 6, 2014 at 5:22pm.

Determine the dimensions, in feet, of his new garden. What would be the equation? Would it be 2w-4=60?

- math -
**Damon**, Monday, January 6, 2014 at 5:32pmTwo equations

L = 2 W - 4

2 L + 2 W = 60

so

2 (2W-4) + 2 W = 60

4 W - 8 + 2 W = 60

6 W = 68

W = 11 1/3 = 11 feet 4 inches

L = 22 2/3 - 4 = 18 2/3 = 18 feet 4 inches

- math -
**jeffery**, Monday, January 6, 2014 at 5:56pmBut then when I do the perimeter for the width and length I would get more than 60.

- math -
**jeffery**, Monday, January 6, 2014 at 5:58pmOh never mind I see what I did to make it more than 60.

- math -
**jeffery**, Monday, January 6, 2014 at 6:15pmBut wait. How did you get the dimensions for the length and width the way you did?

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**Damon**, Monday, January 6, 2014 at 6:31pmwell, 68/6 is 11.3333333333

and

2(11.333 etc) - 4 is 18.66666666

I will add some comments

Two equations

L = 2 W - 4 given

2 L + 2 W = 60 perimeter of rectangle = 2W+2L

so

2 (2W-4) + 2 W = 60 Use (2W-4) for L

4 W - 8 + 2 W = 60 multiply parentheses out

6 W = 68 adding 8 to both sides and combining like terms

W = 11 1/3 = 11 feet 4 inches dividing by 6

L = 22 2/3 - 4 = 18 2/3 = 18 feet 4 inches by going back to L=2W-4

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