Posted by **jeffery** on Monday, January 6, 2014 at 5:22pm.

David currently has a square garden. He wants to redesign his garden and make it into a rectangle with a length that is 4 feet shorter than twice its width. He decides the perimeter should be 60 feet.

Determine the dimensions, in feet, of his new garden. What would be the equation? Would it be 2w-4=60?

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**Damon**, Monday, January 6, 2014 at 5:32pm
Two equations

L = 2 W - 4

2 L + 2 W = 60

so

2 (2W-4) + 2 W = 60

4 W - 8 + 2 W = 60

6 W = 68

W = 11 1/3 = 11 feet 4 inches

L = 22 2/3 - 4 = 18 2/3 = 18 feet 4 inches

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**jeffery**, Monday, January 6, 2014 at 5:56pm
But then when I do the perimeter for the width and length I would get more than 60.

- math -
**jeffery**, Monday, January 6, 2014 at 5:58pm
Oh never mind I see what I did to make it more than 60.

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**jeffery**, Monday, January 6, 2014 at 6:15pm
But wait. How did you get the dimensions for the length and width the way you did?

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**Damon**, Monday, January 6, 2014 at 6:31pm
well, 68/6 is 11.3333333333

and

2(11.333 etc) - 4 is 18.66666666

I will add some comments

Two equations

L = 2 W - 4 given

2 L + 2 W = 60 perimeter of rectangle = 2W+2L

so

2 (2W-4) + 2 W = 60 Use (2W-4) for L

4 W - 8 + 2 W = 60 multiply parentheses out

6 W = 68 adding 8 to both sides and combining like terms

W = 11 1/3 = 11 feet 4 inches dividing by 6

L = 22 2/3 - 4 = 18 2/3 = 18 feet 4 inches by going back to L=2W-4

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