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March 29, 2015

March 29, 2015

Posted by **math help** on Friday, January 3, 2014 at 8:18am.

- math -
**Steve**, Friday, January 3, 2014 at 5:50pmDraw a diagram.

T = top of tower

B = base of tower

D = point 240' downhill

draw a right triangle with hypotenuse TD. Let E be the right angle.

From the law of sines,

125/sin 25° = 240/sin ∠T

∠T is angle DTB

∠T = 54°

Now you have angle T, since

∠TDB + ∠BDE + ∠DTB = 90°

25° + ∠BDE + 54° = 90°

∠BDE = 11° is the angle you want.

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