Posted by ... on Thursday, January 2, 2014 at 9:43pm.
If you end up with
some x equals something, then there will be one solution
e.g. #4
4(x+3)+2x = x-8
4x + 12 + 2x = x-8
5x = -20 ----> some x equals something
x = -4 -----> one solution
if your x term drops out, and you end up with a true statement, there will be an infinite number of solutions
if your x drops out, but you end up with a False statement, there is no solution.
e.g. #2
3(y-9) = 2y - 9 + y
3y - 27 = 3y - 9
-27 = -9 , what do you think, is it true or false ??
do the others the same way
1.
2 ( x - 3 ) = 2 x
2 * x - 2 * 3 = 2 x
2 x - 6 = 2 x subtract 2 x to both sides
2 x - 6 - 2 x = 2 x - 2 x
- 6 = 0
False.
No solutions
2.
3 ( y - 3 ) = 2 y - 9 + y
3 * y - 3 * 3 = 2 y - 9 + y
3 y - 9 = 3 y - 9
True for all values of y.
infinitely many solutions
3.
10 x - 2 - 6 x = 3 x - 2 + x
10 x - 6 x - 2 = 3 x + x - 2
4 x - 2 = 4 x - 2
True for all values of x.
infinitely many solutions
4.
4 ( x + 3 ) + 2 x = x - 8
4 * x + 4 * 3 + 2 x = x - 8
4 x + 12 + 2 x = x - 8
6 x + 12 = x - 8 Subtract x to both sides
6 x + 12 - x = x - 8 - x
5 x + 12 = - 8 Subtract 12 to both sides
5 x + 12 - 12 = - 8 - 12
5 x = - 20 Divide both sides by 5
5 x / 5 = - 20 / 5
x = - 4
one solution
Thank you sooooo much guys!!! Got 100%!
B
C
C
A
100%
Trust me