Posted by Cambridge on .
Prove algebraically that w+z is less than or equal to w+z for any complex numbers w and z, where  is the magnitude.
After letting w = a+bi and z = c + di and doing some plugging in etc. I got that
acbd <= b^2 + sqrt (a^2+b^2)(c^2+d^2) + d^2
But is my proof complete? I know logically sqrt (a^2+b^2)(c^2+d^2) is a bit less than ac+ad+bc+bd but now what?

Complex numbers 
Steve,
There are lots of proofs of the triangle inequality. One such can be found here:
https://www.math.ucdavis.edu/~forehand/67_summer2012_files/triangle%20inequality.pdf