Wednesday

January 28, 2015

January 28, 2015

Posted by **Anonymous** on Wednesday, January 1, 2014 at 6:34pm.

- math -
**Steve**, Wednesday, January 1, 2014 at 6:54pmHaven't devised an algebraic solution. Maybe you can work on that after taking a look at the table below, where row #n is the state of the lockers (0=closed, 1=open) after the nth student has gone by. The last line is the number of times each locker was touched.

01: 11111111111111111111

02: 10101010101010101010

03: 10001110001110001110

04: 10011111001010011111

05: 10010111011010111110

06: 10010011011110111010

07: 10010001011111111010

08: 10010000011111101010

09: 10010000111111101110

10: 10010000101111101111

11: 10010000100111101111

12: 10010000100011101111

13: 10010000100001101111

14: 10010000100000101111

15: 10010000100000001111

16: 10010000100000011111

17: 10010000100000010111

18: 10010000100000010011

19: 10010000100000010001

20: 10010000100000010000

1 2 2 3 2 4 2 4 3 4 2 6 2 4 4 5 2 6 2 6

- math -
**Anonymous**, Wednesday, January 1, 2014 at 6:59pmthanks Steve And Happy new year and God bless you

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