A 395.0 g block is dropped onto a vertical spring with a spring constant k = 252.0 N/m. The block becomes attached to the spring, and the spring compresses 0.29 m before momentarily stopping. While the spring is being compressed, what work is done by the block's weight?
What work is done by the spring?
What was the speed of the block just before it hit the spring?
Physics - please help!! - bobpursley, Monday, December 30, 2013 at 8:45am
The energy in the spring at stopping has to be be equal to the KE when hitting the springl.
1/2 k (.29^2)=1/2 mass*V^2=work done by spring