How much heat is absorbed when 500g of water goes from 25 to 35 degrees
well, how many cal/g°C ?
To determine the amount of heat absorbed by the water, you can use the equation:
Q = mcΔT
Where:
Q is the amount of heat absorbed or released
m is the mass of the water
c is the specific heat capacity of water
ΔT is the change in temperature of the water
First, let's determine the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.
Now, let's calculate the amount of heat absorbed by the water:
m = 500g (given mass of water)
ΔT = 35°C - 25°C = 10°C (change in temperature)
Q = (500g) x (4.18 J/g°C) x (10°C)
Q = 20900 J
Therefore, when 500g of water goes from 25 to 35 degrees, it absorbs 20,900 joules of heat.